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tcc:tldr:e1036

tcc: Directly run an input file like a script and pass arguments to it.
$ tcc -run ${path-to-source_file-c} ${arguments}
try on your machine

The command you provided: "tcc -run ${path-to-source_file-c} ${arguments}" is a command that uses the Tiny C Compiler (TCC) to compile and execute a C source file.

Here is a breakdown of the command:

  • "tcc" is the command to invoke the Tiny C Compiler.
  • "-run" is an option passed to TCC, indicating that the source file should be compiled and immediately executed.
  • "${path-to-source_file-c}" is a placeholder that should be replaced with the actual path to the C source file you want to compile and run. It should have the ".c" file extension.
  • "${arguments}" is a placeholder that should be replaced with any arguments you want to pass to the compiled program when it is executed. These arguments are optional and can include items like command-line parameters or input file names.

To use this command, you need to replace the placeholders with the appropriate values for your use case. For example, if your C source file is located at "/path/to/myfile.c" and you want to pass the argument "input.txt", you would use the modified command:

tcc -run /path/to/myfile.c input.txt

This would compile the "myfile.c" source file and immediately execute the resulting program, passing "input.txt" as an argument.

This explanation was created by an AI. In most cases those are correct. But please always be careful and never run a command you are not sure if it is safe.
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