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coproc:tldr:4537d

coproc: Write to a specific coprocess `stdin`.
$ echo "${input}" >&"$${{name}[1]}"
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This command is a shell command that uses the echo command to print the value of the variable ${input} to the file descriptor specified by the value of the variable $${{name}[1]}.

Let's break down the command step by step:

  1. ${input}: This is a shell variable. The value of this variable will be printed by the echo command.

  2. "${input}": The value of the ${input} variable is enclosed in double quotes. This is done to ensure that any special characters or spaces in the value are preserved during the echo command.

  3. >&"$${{name}[1]}": This portion has two parts:

    • $${{name}[1]}: This is a shell variable ${name} followed by [1]. It is enclosed in double dollar sign $$ to escape the first dollar, so that it is treated as a literal dollar sign. The [1] indicates that we want the second element of the array variable ${name} (assuming ${name} is an array variable).

    • >&: This is a redirection operator in the shell. >& redirects the standard output of the command (echo "${input}" in this case) to the specified file descriptor.

So, overall, the command takes the value of the ${input} variable, encloses it in quotes to preserve special characters, and then redirects the output to the specified file descriptor, which is determined by the value of the array variable ${name}[1].

This explanation was created by an AI. In most cases those are correct. But please always be careful and never run a command you are not sure if it is safe.
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