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go-version:tldr:63dc4

go-version: Print the Go version used to build the named executable file.
$ go version ${path-to-executable}
try on your machine

The command "go version ${path-to-executable}" is not a valid command in the Go programming language.

However, if you meant to ask about the "go version" command in Go, it is a built-in command that prints the Go version information. When you run "go version" without any arguments, it will display the version of the Go compiler and other related build information.

For example, executing "go version" might display something like this:

go version go1.17 linux/amd64

The "${path-to-executable}" part in your command seems to be a placeholder for a specific path to the Go executable file. In a valid command, you would replace "${path-to-executable}" with the actual path to the Go executable.

This explanation was created by an AI. In most cases those are correct. But please always be careful and never run a command you are not sure if it is safe.
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