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javac:tldr:0fed6
javac: Compile a `.java` file and place the resulting class file in a specific directory.
$ javac -d ${path-to-directory} ${file-java}
try on your machine
The command "javac -d ${path-to-directory} ${file-java}" is used to compile a Java source file and specify the destination directory where the compiled class file should be placed.
Here's the breakdown of the command:
- "javac" is the Java Compiler command in JDK (Java Development Kit) used to compile Java source files.
- "-d" is an option flag that stands for "directory" and is used to specify the destination directory for the compiled classes.
- "${path-to-directory}" is a placeholder representing the path to the directory where you want to save the compiled class file. You need to replace this placeholder with the actual path on your system (e.g., "/path/to/directory").
- "${file-java}" is a placeholder representing the name of the Java source file that you want to compile. You need to replace this placeholder with the actual file name (e.g., "MyClass.java").
To use the command, you need to open a command prompt or terminal, navigate to the directory where the Java source file is located, and then execute the command "javac -d ${path-to-directory} ${file-java}". After successful execution, the Java source file will be compiled, and the resulting class file will be saved in the specified destination directory.
This explanation was created by an AI. In most cases those are correct. But please always be careful and
never run a command you are not sure if it is safe.